Question

plzz solve this.....​

Answer 1

Answer:

1.angleAMC=angleBMD(opposite angles are always equal)

DM=CM(given)

MA=MB(M is mid point of AB,given)

so triangleAMC congruent to triangleBMD(by SAS)

2.angleBCA=90degree (given)

angleDBM=angleACM(by cpct)............(1)

BM=CM(by cpct)

so opposite angle of these side will also be equal

AngleMCB=AngleMBC...............(2)

add (1)and(2)

AngleDBC=angleACB=90

3similarly we can prove 3 and4.