Math, asked by skr4aaap96gtr, 1 year ago

plzz solve this . Ans is 1

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Answered by siddhartharao77
1
= \ \textgreater \  Given : \frac{1}{1 +  \sqrt{2} +  \sqrt{3}  } +  \frac{1}{1 -  \sqrt{2} +  \sqrt{3}  }

= \ \textgreater \   \frac{1 +  \sqrt{3} -  \sqrt{2}  }{(1 +  \sqrt{2} +  \sqrt{3})(1 +  \sqrt{3} -  \sqrt{2})    } +  \frac{1 +  \sqrt{2} +  \sqrt{3}  }{(1 +  \sqrt{2} +  \sqrt{3})(1 +  \sqrt{3} -  \sqrt{2})    }

= \ \textgreater \   \frac{(1 +  \sqrt{3} -  \sqrt{2}) + (1 +  \sqrt{2} +  \sqrt{3})   }{(1 +  \sqrt{2} +  \sqrt{3})(1 +  \sqrt{3} -  \sqrt{2})   }


= \ \textgreater \   \frac{2 + 2 \sqrt{3} }{2 + 2 \sqrt{3} }


= > 1.



Hope this helps!

siddhartharao77: :-)
skr4aaap96gtr: it is wrong
siddhartharao77: how
skr4aaap96gtr: sorry it is right
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