Question

plzz solve this . i will mark u the brainlist ​

Answer 1

Answer:

$\frac{2.3^{n+1}*3^{1-n} +7}{25}$

Brainliest!!!

Answer 2

꧁SOLUTION꧂

✧♥༻༺♥✧

$↪ \frac{2 \times 3 {}^{n + 1} + 7 \times 3 {}^{n - 1} }{3 {}^{n + 2} - 2( \frac{1}{3} ) {}^{1 - n} } \\ splitting \: the \: term \: here \\ ↪ \frac{2 \times 3 {}^{n} \times 3 {}^{1} + 7 \times 3 {}^{n} \times 3 {}^{ - 1} }{3 {}^{n} \times 3 {}^{2} - 2(3) {}^{ - (1 - n)} } \\ \\ ↪ \frac{3 {}^{n}(2 \times 3 {}^{1} + 7 \times 3 {}^{ - 1}) }{3 {}^{n} \times 3 {}^{2} - 2 \times 3 {}^{ - 1} \times 3 {}^{n} } \\ \\ ↪ \frac{3 {}^{n}(2 \times 3 {}^{1} + 7 \times 3 {}^{ - 1} ) }{3 {}^{n}(3 {}^{2} - 2 \times 3 {}^{ - 1} )} \\ \\ ↪ \frac{2 \times 3 + \frac{7}{3} }{9 - \frac{2}{3} } \\ \\ ↪ \frac{ \frac{6}{1} + \frac{7}{3} }{ \frac{9}{1} - \frac{2}{3} } ↪ \frac{ \frac{18 + 7}{3} }{ \frac{27 - 2}{3} } \\ \\ ↪ \frac{25}{3} \times \frac{3}{25} = 1$