Question

plzz solve this
it's urgent for 13 points... plzz

Answer 1

@
(x+1)(2x+1)=(x+3)(2x+3)-12
(1)²+(2x+x)1+(2x)(x)=(x+3)(2x+3)-12
1+3x+2x²=(3)²+(x+2x)3+(x)(2x)-12
1+3x+2x×x= 9+9x+2x×x-12
3x-9x+2x²-2x² = 9-12-1
-6x = -4
x=4/6
x=2/3
@:-)

Answer 2

The problem to solve is:

(x+1)(2x+1) =(x+3)(2x+3)-12

First, let's work on the left hand side of your equation, the (x+1)(2x+1) 
This means, for instance, to see if it can be simplified at all.
x+1 evaluates to x+1Multiply x and 2Multiply x and 1The x just gets copied along.The answer is xx2*x evaluates to 2x2*x+1 evaluates to 2x+1Multiplying x+1 by 2x+1 is a classic Algebra problem. Here, you are trying
to multiply two binomials together (two expressions that each contain two terms).
Your book might call this finding the "Product of Two Binomials".
To work this problem, we'll use the "F.O.I.L." method. F.O.I.L. stands
for First, Outer, Inner, Last.
First, we'll multiply the two First terms, the x and 2x together.
Multiply x and 2xMultiply the x and xMultiply x and xCombine the x and x by adding the exponents, and keeping the x, to getThe answer isx × 2x =Second, we'll multiply the two Outer terms, the x and 1 together.
Multiply x and 1Multiply x and 1The x just gets copied along.The answer is xxx × 1 = xThird, we'll multiply the two Inner terms, the 1 and 2x together.
Multiply 1 and 2xMultiply 1 and xThe x just gets copied along.x1 × 2x = 2xx combines with 2x to give 3xLastly, we'll multiply the two Last terms, the 1 and 1 together.
11 × 1 = 1(x+1)*(2*x+1) evaluates to So, all-in-all, the left hand side of your equation can be written as: Now, let's work on the right hand side of your equation, the (x+3)(2x+3)-12
x+3 evaluates to x+3Multiply x and 2Multiply x and 1The x just gets copied along.The answer is xx2*x evaluates to 2x2*x+3 evaluates to 2x+3Multiplying x+3 by 2x+3 is a classic Algebra problem. Here, you are trying
to multiply two binomials together (two expressions that each contain two terms).
Your book might call this finding the "Product of Two Binomials".
To work this problem, we'll use the "F.O.I.L." method. F.O.I.L. stands
for First, Outer, Inner, Last.
First, we'll multiply the two First terms, the x and 2x together.
Multiply x and 2xMultiply the x and xMultiply x and xCombine the x and x by adding the exponents, and keeping the x, to getThe answer isx × 2x =Second, we'll multiply the two Outer terms, the x and 3 together.
Multiply x and 3Multiply x and 1The x just gets copied along.The answer is xxx × 3 = 3xThird, we'll multiply the two Inner terms, the 3 and 2x together.
Multiply 3 and 2xMultiply 1 and xThe x just gets copied along.x3 × 2x = 6x3x combines with 6x to give 9xLastly, we'll multiply the two Last terms, the 3 and 3 together.
Multiply 3 and 313 × 3 = 9(x+3)*(2*x+3) evaluates to 9 - 12 = -3The answer is(x+3)*(2*x+3)-12 evaluates to The right hand side of your equation can be written as: So with these (any) simplifications, the equation we'll set out to solve is:
 =
Move the 1 to the right hand side by subtracting 1 from both sides, like this:
From the left hand side:
1 - 1 = 0The answer isFrom the right hand side:
-3 - 1 = -4
Now, the equation reads:
(2x)2 + 3x = -4 +(2x)2 + 9xThe answer isMove the to the left hand side by subtracting from both sides, like this:
From the left hand side:
 - = 0The answer is 3xFrom the right hand side:
(2x)2-(2x)2 = 0The answer is -4+9x
Now, the equation reads:
3x = -4+9xMove the 9x to the left hand side by subtracting 9x from both sides, like this:
From the left hand side:
3x - 9x = -6xThe answer is -6xFrom the right hand side:
9x - 9x = 0The answer is -4
Now, the equation reads:
-6x = -4 
To isolate the x, we have to divide both sides of the equation by the other variables
around the x on the left side of the equation.
The last step is to divide both sides of the equation by -6 like this:
To divide x by 1The x just gets copied along in the numerator.The answer is x-6x ÷ -6 = x-4 ÷ -6 = 2/3The solution to your equation is:
x = 2/3