Question

plzz solve this log problem as soon as possible​

Answer 1

given:

a²+b²=7ab

adding 2ab on both sides

a²+b²+2ab=7ab+2ab

(a+b)²=9ab

(a+b)=3√ab

1/3(a+b)=1/3*3√ab=√ab

thus,

log[1/3(a+b)]

=>log √ab (from above)

=>log ab^½

=>½ log ab (power law)

=>½ (log a+log b) (product law)