plzz solve this Q-9
Attachments:
Answers
Answered by
1
d1 = 500 m
d2 = 200 m
t1 = 2.10min = 130 sec
t2 = 1 min = 60 sec
(i) Avg. v during 2.10 min = distance/ time
= 500 / 130 = 3.846 m / s ......... ANS (I)
(ii) Avg. v during the whole journey = tot. distance / tot. time
= ( 500+200)/( 130+60)
= 700/ 190
= 3.684 m / s. ...........ANS (II)
HOPE IT WILL HELP YOU. . . . . . . . . . . .
PLZ MARK MY ANSWER AS BRAINLIEST AS SOON AS POSSIBLE! ! ! ! ! ! ! ! !
d2 = 200 m
t1 = 2.10min = 130 sec
t2 = 1 min = 60 sec
(i) Avg. v during 2.10 min = distance/ time
= 500 / 130 = 3.846 m / s ......... ANS (I)
(ii) Avg. v during the whole journey = tot. distance / tot. time
= ( 500+200)/( 130+60)
= 700/ 190
= 3.684 m / s. ...........ANS (II)
HOPE IT WILL HELP YOU. . . . . . . . . . . .
PLZ MARK MY ANSWER AS BRAINLIEST AS SOON AS POSSIBLE! ! ! ! ! ! ! ! !
Similar questions