Question

plzz solve this question

Answer 1

Given a = root 10 + root 5/root 10 - root 5

              = (root 10 + root 5)(root 10 + root 5)/(root 10 - root5)(root 10 + root 5)

We know that (a -b)(a+b) = a^2 - b^2.

              = (root 10 + root 5)^2/(root ((10)^2 - (5)^2)

We know that (a+b)^2 = a^2 + b^2 + 2ab

             = (10 root 2 + 15)/5

             = 5(2 root 2 + 3)/5

            = 2 root 2 + 3.    ----------------- (1)



Given b = root 10 - root 5/root 10 + root 5

              = (root 10 - root 5)(root 10 - root 5)/(root 10 + root 5)(root 10 - root 5)

              = (root 10 - root 5)^2/5

             = 15 - 10 root 2/5

             = 5(3 - 2 root 2)/5

             = 3 - 2 root 2    ------------- (2)


Then root a - root b - 2root a rootb

          = root (2 root 2 + 3) - root(3 - 2 root 2) - 2root(2 root 2 + 3)(3 - 2 root 2)

         = root 2 + 1 - (root 2 - 1) - 2

         = root 2 + 1 - root 2 + 1 - 2

         = 2 - 2

         = 0.


Hope this helps!

Answer 2

i have solved the answer in the solution

hope it helps :)

pls mark as verified by expert s

T!—!ANKS!!!