Question

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Answer 1

Bonjour ❤️

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Given :-

SR || PQ

SP || RQ

=> PQRS is a parallelogram.

now,

In ∆ PQR and ∆ PRS,

SR = PQ ( sides of a ||gm are parallel and equal)

PSR = RQP ( opposite angles of a ||gm are equal )

SP = RQ ( sides of ||gm are parallel and equal)

hence,

∆ PQR ≈ ∆ PRS .........( by S.A.S ) PROVED//

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Answer 2

Heya ur solution
In the adjoining figure it is given that

PS = QR and PQ = SR
so in the triangle PQR and Triangle PRS, WE have
PS = QR ( Given)

PQ = SR ( Given)
And
PR is the common side
Therefore triangle PQR is congruent to triangle PRS by sss

Another method
Since SR // PQ
this shows that angle SRP is equal to angle RPQ (alternate interiors )
Now in triangle PQR and in triangle PRS
SR = PQ ( GIVEN)
PR is the common side
AND
angle SRP = angle RPQ ( from above)
Therefore

Triangle PQR is congruent to triangle PRS through S. A. S criteria

HOPE this helps
Plz mark it as brainliest