plzz solve this question properly with steps .....
Answers
Density = 1 gm/ml
We know that,
18 g of water contain 6.022* 10^23 water molecules
Therefore,
1 gm contains = 6.022*10^23 / 18 water molecules
as per density given 1 gm equivalent to 1 ml
Therefore, volume of 6.022*10^23 /18 water molecules = 1 ml = 10^-6 cm3
So volume of one water molecule = 10^-6 * 18 /(6.022 *10^23)
= 3 * 10^29
2) Given
Density = 1 gm/ml
We know that,
18 g of water contain 6.022* 10^23 water molecules
Therefore,
1 gm contains = 6.022*10^23 / 18 water molecules
as per density given 1 gm equivalent to 1 ml
Therefore, volume of 6.022*10^23 /18 water molecules = 1 ml = 10^-6 cm3
So volume of one water molecule = 10^-6 * 18 /(6.022 *10^23)
= 3 * 10^29
Volume of sphere = 4/3 π r^3
3 * 10^29 = 1.34 * 3.14 * r^3
r^3 = 0.70 * 10^29
r = 1.91 * 10^-4
3) We have Vol. of Oxygen = Half of Vol. Of Water Molecule...
So Vol. of Oxygen = 3*10^-23 cm^3/2
= 1.5 x 10^-23 cm^3
Volume of sphere = 4/3 π r^3
1.5 * 10^29 = 1.34 * 3.14 * r^3
r^3 = 0.36* 10^29
r = 0.71 * 10^-4