plzz solve this question ..Q 2
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"The Area of Quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm
Area of Quadrilateral = Area of ΔABC + Area of ΔADC Area of ΔABC Area of triangle = √(s (s−a) (s−b) (s −c))
s is the semi-perimeter
a, b, c are the sides of the triangle
Here, , and a, b, c are the sides of the triangle
Here, a = 3 , b = 4, c = 5 S = ( + + )/2 Area of Δ ABC = √(( −)( −)( −))
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