plzz solve this with steps ....plzzzz
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5y+3y+2y=180°
10y=180°
y=18°
Therefore,angle aod=5y=5×18=90
angleDoc=3y= 3×18=54
and angle COB=2y=2×18=36
10y=180°
y=18°
Therefore,angle aod=5y=5×18=90
angleDoc=3y= 3×18=54
and angle COB=2y=2×18=36
mythili8:
wrong answer
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In the above question
Angle BOC and COD and DOA=
= 5y+2y+3y=180
= 5y+5y=180
= 10y=180
y=180/10
y = 18 degree
Angle BOC and COD and DOA=
= 5y+2y+3y=180
= 5y+5y=180
= 10y=180
y=180/10
y = 18 degree
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