Math, asked by Anonymous, 10 months ago

plzz sovle questions .. l need help...​

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Answered by Mihir1001
3

\huge{\underline{\mathfrak{\textcolor{blue}{Answer :}}}}

\huge\boxed{\fcolorbox{red}{pink}{41/35}}

\huge{\underline{\mathrm{\textcolor{red}{Step-by-step \:  \: explanation :}}}}

\LARGE{\underline{\mathtt{\textcolor{violet}{Given :-}}}}

  • product of two rational numbers  = \large{ -  \frac{12}{35} }

  • one of the rational number  = \large{ \frac{3}{5} }

\LARGE{\underline{\mathtt{\textcolor{green}{To \:  \: find :-}}}}

  • absolute value of the difference of the two rational numbers .

\LARGE{\underline{\mathtt{\textcolor{teal}{Concept \:  \: used :-}}}}

  • Real Numbers

\LARGE{\underline{\mathtt{\textcolor{blue}{Solution :-}}}}

let the other rational number be x.

 \therefore  \: ,A/Q,

 \longmapsto \Large{ \frac{3}{5}  \times x =  -  \frac{12}{35} }

 \implies \Large{ x =  -  \frac{12}{35}  \times  \frac{5}{3} }

 \implies \Large{ x =  -  \frac{ {}^{4}  \:  \cancel{12} }{_7 \:  \cancel{35} }  \times  \frac{ \cancel{5}  \:  {}^{1} }{ \cancel{3}  _1 } }

 \implies \Large{ x =  -  \frac{4}{7} }

Hence, \bold{ \frac{3}{5} } and \bold{ -  \frac{4}{7} } are the two rational numbers.

Thus,

absolute value of the difference of these rational numbers

 = \Large{ | \frac{3}{5}  -  \left(  -  \frac{4}{7}  \right) | }

 = \Large{ | \frac{3}{5}  +  \frac{4}{7} | }

 = \Large{ | \frac{(3)(7) + (4)(5)}{(5)(7)} | }

 = \Large{ | \frac{21 + 20}{35} | }

 = \Large{ | \frac{41}{35} | }

 = \Large{ \frac{41}{35} }

\LARGE{\underline{\mathtt{\textcolor{magenta}{Conclusion :-}}}}

  • absolute value of the required difference  = \Large{ \left(  \frac{41}{35}  \right) } = \Large{ \left( 1 \frac{6}{35}  \right) }

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