Question

plzz tell this answer. quickly

Answer 1

take Common the lowest power in each case

Answer 2

$\frac{ {2}^{30} + {2}^{29} + {2}^{28} }{ {2}^{31} + {2}^{30} - {2}^{29} } = \frac{7}{10} \\ \\ \frac{ {2}^{28} ({2 }^{2} + 2 + {2}^{0} ) }{ {2}^{29}( {2}^{2} + 2 + {2}^{0} ) } \\ \\ \frac{ {2}^{28} (4 + 2 + 1) }{ {2}^{29}(4 + 2 - 1) } \\ \\ \frac{ {2}^{28} \times 7 }{ {2}^{29} \times 5 } \\ \\ {2}^{28 - 29} \times \frac{7}{5} \\ \\ {2}^{ - 1} \times \frac{7}{5} \\ \\ \frac{1}{2} \times \frac{7}{5} \\ \\ \frac{7}{10}$

Hence Proved