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as arc length = theta × radius
s o arc length = theta × r
IN TRIANGLE OAB
TAN THETA = AB/ R
AB = TAN THETA × r
As oc = r
and cos theta= r/OB
so ob = r sec theta
ob = oc + cb
= r + BC
BC = rsectheta - r
SO PERIMETER = RTAN THETA + RSECTHETA -R + THETA R
2)AREA OF OAB= 1/2 AB .R
= 1/2 TAN THETA×R × R
R.R TAN THETA/2
AS SECTOR AREA = pie .r.r theta/360
= r.r theta/2
so area= r.r tan theta/2 - r.r theta/2
=
s o arc length = theta × r
IN TRIANGLE OAB
TAN THETA = AB/ R
AB = TAN THETA × r
As oc = r
and cos theta= r/OB
so ob = r sec theta
ob = oc + cb
= r + BC
BC = rsectheta - r
SO PERIMETER = RTAN THETA + RSECTHETA -R + THETA R
2)AREA OF OAB= 1/2 AB .R
= 1/2 TAN THETA×R × R
R.R TAN THETA/2
AS SECTOR AREA = pie .r.r theta/360
= r.r theta/2
so area= r.r tan theta/2 - r.r theta/2
=
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