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1.the lengths of AC and BD are 6 and 4 respectively
because the diagonals bisect each other so OA=OC=3 and OB=OD=2
then AC=OA+OC=3+3=6 and BD=OB+OD=2+2=4
2.Diagonals of a parallelogram are perpendicular to each other. Each diagonal seperates the parallelogram into two congruent triangles.
3.Given angles are not the angles of quadrilateral becoz their sum(110+80+95+70) is 355. In a quadrilateral sum of all angles should be 360.
4.it may be Rhombus
5.It may be square
because the diagonals bisect each other so OA=OC=3 and OB=OD=2
then AC=OA+OC=3+3=6 and BD=OB+OD=2+2=4
2.Diagonals of a parallelogram are perpendicular to each other. Each diagonal seperates the parallelogram into two congruent triangles.
3.Given angles are not the angles of quadrilateral becoz their sum(110+80+95+70) is 355. In a quadrilateral sum of all angles should be 360.
4.it may be Rhombus
5.It may be square
brunila:
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