Question

plzzz ans.....CONGRUENCE OF TRIANGLES

Answer 1

AC =DE (given)

Angle ACB = angle FDE (given)

Angle ABC= angle DFE
(As AB is parallel to FE then, angle ABC mist equal angle DFE by alternate interior angle)


So now,
Triangle ACB is congurent to triangle EDF

Now,


i) AB=FE (by C.P.C.T)

ii) BD+DC = FD+DC (by C.P.C.T)
then, BD = FD

Answer 2

In trianlge ABC & triangle EFD. :-
1.angle BCA = angle FDE. ( GIVEN)
2.AC = DE. ( GIVEN)
3. given AB parallel FE
THEREFORE , angle ABC = angle EFD. (Alternative Interior Angle)

Hence triangle ABC CONGRUENT triangle EFD

i.AB = FE ( CPCT)
ii.BC = FD
BD + DC = FC + DC( BC = BD + DC & FD = FC + DC)
substracting DC both side we get :-
BD = FC