Question

plzzz ans .....Logarithms......Thnk u

Answer 1

Hey there !!

logₓ49-logₓ7+logₓ1/343+2=0

We know that 

                logₐb=logb/loga  and logₓ(1/343) = logₓ1-logₓ343 and logₓ1=0
                    

So, 

log49/logx -log7/logx+log1-logₓ343+2=0



49=7²    343= 49*7=7²*7=7³

log7²/logx-log7/logx+0-log7³/logx+2=0

2log7/logx-log7/logx-3log7/logx+2=0


1/logx(2log7-log7-3log7)+2=0

1/logx(-2log7)+2=0

-2log7/logx = -2

2log7/logx = 2

log7²=2logx

log7²=logx²

 x²=7²


 ⇒⇒⇒x=7 



Hope this helped you...................