Plzzz ans....Logarithms ....Thnk you
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Hey there !!!!
3/2(loga)+2/3(logb)-1=0
3/2(loga)+2/3(logb)=1
We know that xlogt=logtˣ
So,
loga³/₂+logb²/₃=log10
loga³/₂*b²/₃=log10
a³/₂*b²/₃=10----Equation 1
Cubing equation 1 on both sides
a³*³/₂*b²*³/₃=10³
a⁹/₂*b²=1000-----Equation 2
Now squaring equation 2 on both sides
(a⁹/₂*b²)²=(1000)²
a⁹*²/₂*b⁴=10³*²
a⁹*b⁴=10⁶
Hope this helped you....................
3/2(loga)+2/3(logb)-1=0
3/2(loga)+2/3(logb)=1
We know that xlogt=logtˣ
So,
loga³/₂+logb²/₃=log10
loga³/₂*b²/₃=log10
a³/₂*b²/₃=10----Equation 1
Cubing equation 1 on both sides
a³*³/₂*b²*³/₃=10³
a⁹/₂*b²=1000-----Equation 2
Now squaring equation 2 on both sides
(a⁹/₂*b²)²=(1000)²
a⁹*²/₂*b⁴=10³*²
a⁹*b⁴=10⁶
Hope this helped you....................
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