Question

plzzz ans me......... check whether 6n can end with the digit 0 for any natural number n.

Answer 1

If a no ends with zero then it has five as one of its factor.
10 =2 x 5
40 = 2x 2 x 2 x5
Now by fundamental theorem of arithmetic:
6^n =(2 x 3)^n
= 2^n x 3^n
Clearly 6^n does not contain 5 as its factor therefore it cannot end in zero.

Answer 2

☆Hey friend!!!☆

here is your answer ☞
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If any number ends with the digit 0, it should be divisible by 10 or in other words, it will also be divisible by 2 and 5 as 10 = 2 × 5

Prime factorisation of 6n = (2 ×3)n

It can be observed that 5 is not in the prime factorisation of 6n.

Hence, for any value of n, 6n will not be divisible by 5.

hope it will help you ☺☺☺☺


Devil_king ▄︻̷̿┻̿═━一

Therefore, 6n cannot end with the digit 0 for any natural number n.