Question

plzzz ans....physics....plzzz ans third part

Answer 1

Given:
initial speed = u= 25m/s
time = t1=5sec
a=0 m/s2
case I)
distance travelled =s1=?
from second equation of motion
s1=ut+1/2 at^2
=25×5 +0
=125m

case 2)
final velocity= V=0m/s
From FIRST equation of motion:
V=u+at
0=25+ax10
10xa = -25
a=-2.5 m/s2
retardation =2.5 m/s2

case 3:

s= ut +1\2at2
=25×10+1/2 (-2.5)10*10
=250-125
=125m