plzzz ans....Quadratic equation....thnk u
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2
2x articles cost = rs ( 5x + 54 )
then , cost of 1 article would be = rs ( 5x + 54 ) / 2x
x+2 articles cost = rs ( 10x - 4 )
then, cost of 1 article = rs ( 10x - 4 ) / x+2
since , both are same articles . Hence , we can equate the above equations
=> (5x+54) / 2x = (10x-4) / (x+2)
=> (5x+54)(x+2) = (10x-4)(2x)
=> 5x² + 10x + 54x + 108 = 20x² - 8x
=> 20x² - 5x² - 8x - 64x - 108 = 0
=> 15x² - 72x - 108 = 0
=> 3 ( 5x² - 24x - 36 ) = 0
=> 5x² - 24x - 36 = 0/3 = 0
=> 5x² - 30x + 6x - 36 = 0
=> 5x ( x - 6 ) + 6 ( x - 6 ) = 0
=> ( x - 6 ) ( 5x + 6 ) = 0
( x - 6 ) = 0 => x = 6
( 5x + 6 ) = 0 => x = -6/5
since , x cannot be in negative
therefore , x = 6
hope this helps
then , cost of 1 article would be = rs ( 5x + 54 ) / 2x
x+2 articles cost = rs ( 10x - 4 )
then, cost of 1 article = rs ( 10x - 4 ) / x+2
since , both are same articles . Hence , we can equate the above equations
=> (5x+54) / 2x = (10x-4) / (x+2)
=> (5x+54)(x+2) = (10x-4)(2x)
=> 5x² + 10x + 54x + 108 = 20x² - 8x
=> 20x² - 5x² - 8x - 64x - 108 = 0
=> 15x² - 72x - 108 = 0
=> 3 ( 5x² - 24x - 36 ) = 0
=> 5x² - 24x - 36 = 0/3 = 0
=> 5x² - 30x + 6x - 36 = 0
=> 5x ( x - 6 ) + 6 ( x - 6 ) = 0
=> ( x - 6 ) ( 5x + 6 ) = 0
( x - 6 ) = 0 => x = 6
( 5x + 6 ) = 0 => x = -6/5
since , x cannot be in negative
therefore , x = 6
hope this helps
Answered by
3
Hello Radhika
Your answer is.....
2x Costs ₹ ( 5x + 54 )
So 1 article costs
Let this be equation (1)
Now,
( x + 2 ) articles costs ₹ ( 10x - 4 )
Then 1 article costs
Let this be equation (2)
In question, it is given that both are costs same ,
so, Equation (1) = Equation (2)
x cannot be in negative forms
therefore ,
x = 6
Hope it helps
Your answer is.....
2x Costs ₹ ( 5x + 54 )
So 1 article costs
Let this be equation (1)
Now,
( x + 2 ) articles costs ₹ ( 10x - 4 )
Then 1 article costs
Let this be equation (2)
In question, it is given that both are costs same ,
so, Equation (1) = Equation (2)
x cannot be in negative forms
therefore ,
x = 6
Hope it helps
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