plzzz ans....thnk u....factorise
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(a^2-a)(4a^2-4a-5)-6
(a^2-a)[4(a^2-a)-5]-6
Let a^2-a=x
=x[4x-5]-6
=4x^2-5x-6 (Split the middle term)
=4x^2-8x+3x-6 (4 * -6 = -24)
=4x(x-2)+3(x-2)
=(4x+3)(x-2) (Substitute again)
= [4(a^2-a)+3](a^2- a- 2)
= (4a^2-4a+3)(a^2-2a+a-2)
=(4a^2-4a+3)[a(a+1)-2(a+1)]
=(4a^2-4a+3)(a+1)(a-2)
(a^2-a)[4(a^2-a)-5]-6
Let a^2-a=x
=x[4x-5]-6
=4x^2-5x-6 (Split the middle term)
=4x^2-8x+3x-6 (4 * -6 = -24)
=4x(x-2)+3(x-2)
=(4x+3)(x-2) (Substitute again)
= [4(a^2-a)+3](a^2- a- 2)
= (4a^2-4a+3)(a^2-2a+a-2)
=(4a^2-4a+3)[a(a+1)-2(a+1)]
=(4a^2-4a+3)(a+1)(a-2)
sanj2:
give ans plzzz
(a^2-a)(4a^2-4a-5)-6
(a^2-a)[4(a^2-a)-5]-6
Let a^2-a=x
=x[4x-5]-6
=4x^2-5x-6 (Split the middle term)
=4x^2-8x+3x-6 (4 * -6 = -24)
=4x(x-2)+3(x-2)
=(4x+3)(x-2) (Substitute again)
= [4(a^2-a)+3](a^2- a- 2)
= (4a^2-4a+3)(a^2-2a+a-2)
=(4a^2-4a+3)[a(a+1)-2(a+1)]
=(4a^2-4a+3)(a+1)(a-2)
(a^2-a)[4(a^2-a)-5]-6
Let a^2-a=x
=x[4x-5]-6
=4x^2-5x-6 (Split the middle term)
=4x^2-8x+3x-6 (4 * -6 = -24)
=4x(x-2)+3(x-2)
=(4x+3)(x-2) (Substitute again)
= [4(a^2-a)+3](a^2- a- 2)
= (4a^2-4a+3)(a^2-2a+a-2)
=(4a^2-4a+3)[a(a+1)-2(a+1)]
=(4a^2-4a+3)(a+1)(a-2)
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