Question

plzzz ans....Thnk u....PROVE THE FOLLOWING

Answer 1

used identity

( in LHS )

cosec∅ = 1 / sin∅

( in RHS )

Sin²∅ + cos²∅ = 1

a² - b² = ( a - b ) ( a + b )

Answer 2

HELLO DEAR


$\frac{1 + \cosec( \alpha ) }{ \cosec( \alpha ) } = \frac{1}{cosec \alpha } + \frac{ \cosec( \alpha ) }{ \cosec( \alpha ) } \\ \\ = ( \sin( \alpha ) + 1) \\ \\ =( \sin \alpha + 1 )\times \frac{1 - \sin( \alpha ) }{1 - \sin( \alpha ) } \\ \\ = \frac{( {1} - {sin}^{2} \alpha )}{1 - \sin( \alpha ) } \\ \\ = \frac{ {cos}^{2} \alpha }{1 - \sin \alpha } \: \: .....using ( {sin}^{2} \alpha + {cos}^{2} \alpha = 1)$
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