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Answers
Q 2) x2-5x+k
Here, a=1, b=-5 and c=k
Now, α+ β = -b/a= -(-5)/1= 5
α*β = c/a= k/7= k
Now,α - β =1
Squaring both sides, we get,
(α - β)2=12
⇒ α2 + β2 - 2αβ = 1
⇒ (α2 + β2 + 2αβ) - 4αβ = 1
⇒ (α +β)2 -4αβ =1
⇒ (5)2-4k=1
⇒ -4k= 7-25
⇒ -4k= -24
⇒ k=6 So the value of k is 6.
(1) Let us assume on the contrary that 5−√3 is rational. Then, there exist prime positive integers a
and b such that
5-√3=a/b
⇒5-a/b=√3
⇒√3 is rational
[∵a,b are integers∴ (5b−a)/b is a rational number]
This contradicts the fact that √3 is irrational.
So, our assumption is incorrect. Hence, 5−√3 is an irrational number.
(6) Basic Proportionality Theorem states that "If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio".
Thales Theorem Statement states that "If a line is drawn parallel to one side of a triangle intersecting the other two sides in distinct points, then the other two sides are divided in the same ratio".