plzzz answer this qu-n
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Let the breadth of the rectangular park be x m.
So, its length = (x + 3) m.
Therefore, the area of the rectangular park = x(x + 3) m2 = (x2 + 3x) m2.
Now, base of the isosceles triangle = x m.
Therefore, its area = ½ × x × 12 = 6x m2.
According to the question,
x2 + 3x = 6x + 4
x2 – 3x – 4 = 0
Using the quadratic formula,
x = 4 or –1
But x ≠ – 1. Therefore, x = 4.
So, the breadth of the park = 4 m and its length will be 7 m.
Verification:
Area of rectangular park = 28 m2
Area of triangular park = 24 m2 = (28 – 4) m2
Plzz mark me brainlist
Let the breadth of the rectangular park be x m.
So, its length = (x + 3) m.
Therefore, the area of the rectangular park = x(x + 3) m2 = (x2 + 3x) m2.
Now, base of the isosceles triangle = x m.
Therefore, its area = ½ × x × 12 = 6x m2.
According to the question,
x2 + 3x = 6x + 4
x2 – 3x – 4 = 0
Using the quadratic formula,
x = 4 or –1
But x ≠ – 1. Therefore, x = 4.
So, the breadth of the park = 4 m and its length will be 7 m.
Verification:
Area of rectangular park = 28 m2
Area of triangular park = 24 m2 = (28 – 4) m2
Plzz mark me brainlist
ashwani381:
plzz
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