Question

plzzz give me answer

Answer 1

cosec(A) = 2 (given),

1/tan(A) + sin(A)/[1 + cos(A)], convert everything into sin and cos,

cos(A)/sin(A) + sin(A)/[1 + cos(A)],

= [cos(A) + cos^2(A) + sin^2(A)]/sin(A)[1 +cos(A)],

= (cos(A) + 1)/sin(A)(cos(A) + 1),

= 1/sin(A) = cosec(A) = 2
It helped u

Answer 2

Answer:

2

Step-by-step explanation:

sin A = 1 / cosec A = 1/2

cos² A = 1 - sin² A = 3/4  =>  cos A = ± √3 / 2

tan A = sin A / cos A = (1/2) / (±√3/2) = ± 1 / √3  (same sign as cos A)

Then

1 / tan A + sin A / ( 1 + cos A )

= ±√3 +  1 / ( 2 ± √3 )

= ±√3 +  ( 2 - ±√3 ) / ( 2² - 3 )

= ±√3 + 2 - ±√3

= 2