Question

plzzz give me immediately answer plz
no 4

Answer 1

x = 180 t + 50 t^2
comparing this with 2nd eq. of motion
s = ut + 1/2at^2
we get u = 180
therefore, initial velocity = 180 ms^-1

Similarly for acceleration
comparing the equations..
we get 1/2 a = 50
a = 50×2 = 100 ms^-2

velocity = v
u = 180
time t = 4s
a = 100
from eq. v = u + at
putting values...
we get v = 580ms^-2