Question

plzzz help in this 6que plzzzzzzzz it's so urgent plzzz frnd

Answer 1

Hey!
Option A is correct.

No. of Na₊ ions=6.02×10²³
Therefore,No. of formula units of Na₂CO₃=6.02×10²³÷2
                                                                   =3.01×10²³
Molar mass of Na₂CO₃=(23×2)+(12×1)+(16×3)
                                      =(46)+(12)+(48)
                                     =106 g/mol
6.02×10²³ formula units of Na₂CO₃ has mass=106 g
Therefore,3.01×10²³ formula units of Na₂CO₃ has mass                                 =(106×3.01×10²³)/(6.02×10²³)
=53 g

    Hence,A is the correct answer.
                                      

Answer 2

1 mole of Na₂CO₃ contains 2 x Avogadro number of Na⁺ ions
                                   
                                       → 2 x 6 x 10²³ Na⁺ ions

But, it is given that number of Na⁺ ions in the sample of Na₂CO₃= 6 x 10²³

It means that 0.5 moles of Na₂CO₃ have been taken.

mass of 0.5 moles of Na₂CO₃ = 0.5 x 106 = 53 grams


Hope it helps