Question

plzzz... help me........ ​

Answer 1

$\sf{\bold{\purple{\star{\underline{\underline{Solution\: 1}}}}}}$

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$\sf : \implies\:{\bold{ 2x^2 - 5x + 3 = 0 }}$

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$\sf : \implies\:{\bold{ 2x^2 - 2x - 3x + 3 = 0 }}$

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$\sf : \implies\:{\bold{ 2x ( x + 1 ) - 3 ( x + 1 )= 0 }}$

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$\sf : \implies\:{\bold{ (2x - 3 ) ( x + 1 ) = 0 }}$

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$\sf : \implies\:{\bold{ 2x - 3= 0 | x + 1 = 0 }}$

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$\sf : \implies\:{\bold{ 2x = 3 | x = - 1 }}$

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$\sf : \implies\:{\bold{ x =\dfrac{3}{2} | x = - 1 }}$

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$\sf{\star{\boxed{\orange{\frak{ x = \dfrac{3}{2} or - 1}}}}}$

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$\sf{\bold{\purple{\star{\underline{\underline{Solution\: 2}}}}}}$

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$\sf : \implies\:{\bold{ 2x^2 - x - 91 = 0 }}$

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$\sf : \implies\:{\bold{ 2x^2 - 14x + 13x - 91 = 0 }}$

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$\sf : \implies\:{\bold{ 2x ( x - 7 ) + 13 ( x - 7)= 0 }}$

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$\sf : \implies\:{\bold{ (2x + 13 ) ( x - 7 ) = 0 }}$

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$\sf : \implies\:{\bold{ 2x + 13 = 0 | x - 7 = 0 }}$

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$\sf : \implies\:{\bold{ 2x = - 13 | x = 7 }}$

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$\sf : \implies\:{\bold{ x =\dfrac{-13}{2} | x = 7 }}$

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$\sf{\star{\boxed{\orange{\frak{ x = \dfrac{-13}{2} or 7}}}}}$

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