Question

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Answer 1

Attachment diagram of the question :—

$\mathtt{\huge{\underline{\red{Question\:?}}}}$

★ Two objects, each of mass 1.5 kg, are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 m s-1 before the collision during which they stick together. What will be the velocity of the combined object after collision?

$\mathtt{\huge{\underline{\green{Answer:-}}}}$

✒ 0 ms-¹ is the velocity of the combined object after collision.

$\mathtt{\huge{\underline{\orange{Solution:-}}}}$

Given :-

Two objects, each of mass 1.5 kg, are moving in the same straight line but in opposite directions.

The velocity of each object is 2.5 m s-1 before the collision during which they stick together.

To Find :-

The velocity of the combined object after collision.

Calculation :-

According to the question :-

Mass of 1 (m1) = 1.5 kg

Mass of 2 (m2) =1.5 kg

Velocity of 1 (u1) = 2.5 m/s

Velocity of 2 (u2) = - 2.5 m/s

U2 is -ve since, U1 & U2 are in opposite direction.

After collision object comes closer ,

Therefore combined mass is,

M = m1 + m2

➝ 1.5 + 1.5

➝ 3 kg

V is the velocity,

V is at same +ve direction so V is same here.

Momentum ,

▶ Before Collision :-

Momentum = M1 + M2

➝ 1.5 × 2.5 + 1.5 × - 2.5

➝ 1.5 × 2.5 - 1.5 × 2.5

➝ 3.75 - 3.75

➝ 0

Hence, Momentum = 0 ..........(1)

▶ After Collision :-

Momentum = total mass × Velocity

➝ Momentum = 3 × v

From (i) Value of momentum is

➝ Momentum = 3 × v

➝ 0 = 3 × v

➝ v = 0/3

➝ v = 0 m/s

The velocity of the combined object after collision is 0 m/s.

________________________________________________

Answer 2

Answer:

★ Two objects, each of mass 1.5 kg, are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 m s-1 before the collision during which they stick together. What will be the velocity of the combined object after collision?

\mathtt{\huge{\underline{\green{Answer:-}}}}

Answer:−

✒ 0 ms-¹ is the velocity of the combined object after collision.

\mathtt{\huge{\underline{\orange{Solution:-}}}}

Solution:−

Given :-

Two objects, each of mass 1.5 kg, are moving in the same straight line but in opposite directions.

The velocity of each object is 2.5 m s-1 before the collision during which they stick together.

To Find :-

The velocity of the combined object after collision.

Calculation :-

According to the question :-

Mass of 1 (m1) = 1.5 kg

Mass of 2 (m2) =1.5 kg

Velocity of 1 (u1) = 2.5 m/s

Velocity of 2 (u2) = - 2.5 m/s

U2 is -ve since, U1 & U2 are in opposite direction.

After collision object comes closer ,

Therefore combined mass is,

M = m1 + m2

➝ 1.5 + 1.5

➝ 3 kg

V is the velocity,

V is at same +ve direction so V is same here.

Momentum ,

▶ Before Collision :-

Momentum = M1 + M2

➝ 1.5 × 2.5 + 1.5 × - 2.5

➝ 1.5 × 2.5 - 1.5 × 2.5

➝ 3.75 - 3.75

➝ 0

Hence, Momentum = 0 ..........(1)

▶ After Collision :-

Momentum = total mass × Velocity

➝ Momentum = 3 × v

From (i) Value of momentum is

➝ Momentum = 3 × v

➝ 0 = 3 × v

➝ v = 0/3

➝ v = 0 m/s

The velocity of the combined object after collision is 0 m/s.

Step-by-step explanation:

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