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Answers
Attachment diagram of the question :—
★ Two objects, each of mass 1.5 kg, are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 m s-1 before the collision during which they stick together. What will be the velocity of the combined object after collision?
✒ 0 ms-¹ is the velocity of the combined object after collision.
Given :-
Two objects, each of mass 1.5 kg, are moving in the same straight line but in opposite directions.
The velocity of each object is 2.5 m s-1 before the collision during which they stick together.
To Find :-
The velocity of the combined object after collision.
Calculation :-
According to the question :-
Mass of 1 (m1) = 1.5 kg
Mass of 2 (m2) =1.5 kg
Velocity of 1 (u1) = 2.5 m/s
Velocity of 2 (u2) = - 2.5 m/s
U2 is -ve since, U1 & U2 are in opposite direction.
After collision object comes closer ,
Therefore combined mass is,
M = m1 + m2
➝ 1.5 + 1.5
➝ 3 kg
V is the velocity,
V is at same +ve direction so V is same here.
Momentum ,
▶ Before Collision :-
Momentum = M1 + M2
➝ 1.5 × 2.5 + 1.5 × - 2.5
➝ 1.5 × 2.5 - 1.5 × 2.5
➝ 3.75 - 3.75
➝ 0
Hence, Momentum = 0 ..........(1)
▶ After Collision :-
Momentum = total mass × Velocity
➝ Momentum = 3 × v
From (i) Value of momentum is
➝ Momentum = 3 × v
➝ 0 = 3 × v
➝ v = 0/3
➝ v = 0 m/s
The velocity of the combined object after collision is 0 m/s.
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Answer:
★ Two objects, each of mass 1.5 kg, are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 m s-1 before the collision during which they stick together. What will be the velocity of the combined object after collision?
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Answer:−
✒ 0 ms-¹ is the velocity of the combined object after collision.
\mathtt{\huge{\underline{\orange{Solution:-}}}}
Solution:−
Given :-
Two objects, each of mass 1.5 kg, are moving in the same straight line but in opposite directions.
The velocity of each object is 2.5 m s-1 before the collision during which they stick together.
To Find :-
The velocity of the combined object after collision.
Calculation :-
According to the question :-
Mass of 1 (m1) = 1.5 kg
Mass of 2 (m2) =1.5 kg
Velocity of 1 (u1) = 2.5 m/s
Velocity of 2 (u2) = - 2.5 m/s
U2 is -ve since, U1 & U2 are in opposite direction.
After collision object comes closer ,
Therefore combined mass is,
M = m1 + m2
➝ 1.5 + 1.5
➝ 3 kg
V is the velocity,
V is at same +ve direction so V is same here.
Momentum ,
▶ Before Collision :-
Momentum = M1 + M2
➝ 1.5 × 2.5 + 1.5 × - 2.5
➝ 1.5 × 2.5 - 1.5 × 2.5
➝ 3.75 - 3.75
➝ 0
Hence, Momentum = 0 ..........(1)
▶ After Collision :-
Momentum = total mass × Velocity
➝ Momentum = 3 × v
From (i) Value of momentum is
➝ Momentum = 3 × v
➝ 0 = 3 × v
➝ v = 0/3
➝ v = 0 m/s
The velocity of the combined object after collision is 0 m/s.
Step-by-step explanation: