Question

plzzz help me out guys

Answer 1

( i ). Sum of the zeroes of polynomial = - b / a

=> - 7 / 3

( ii ). x^2 - 169

( x^2 ) - ( 13) ^2 = 0

x^2 = 13^2

x = +-13

Answer 2

1. sum of zeroes is -b/a = -7/3

2. x^2 - 169 = 0
x^2 - 13^2 = 0
(x-13)×(x+13) = 0

so zeroes or roots of this eq. is x = +13 & -13


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