plzzz help me out guys
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( i ). Sum of the zeroes of polynomial = - b / a
=> - 7 / 3
( ii ). x^2 - 169
( x^2 ) - ( 13) ^2 = 0
x^2 = 13^2
x = +-13
=> - 7 / 3
( ii ). x^2 - 169
( x^2 ) - ( 13) ^2 = 0
x^2 = 13^2
x = +-13
royalrajput91:
hyyy
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1. sum of zeroes is -b/a = -7/3
2. x^2 - 169 = 0
x^2 - 13^2 = 0
(x-13)×(x+13) = 0
so zeroes or roots of this eq. is x = +13 & -13
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2. x^2 - 169 = 0
x^2 - 13^2 = 0
(x-13)×(x+13) = 0
so zeroes or roots of this eq. is x = +13 & -13
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