Question

plzzz help me to find these two solutions

Answer 1

Hi friend here is ur query....
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8.) As we know
momentum (p)=m.v
m=mass
v= velocity

And k.e = ½m.v²
=½*(m².v²/m)
k.e=½(p²/m)

As mass is constant

hence k.e is directly proportional to momentum ²

Now k.e1/k.e2 = (p1)²/(p2)²

k.e1/k.e2=[p1/(p1+p1/2) ]²

or k.e1/k.e2=4/9

or k.e2=2.25 k.e1

or increase in k.e =[(2.25-1)k.e1/k.e1]*100%
1.25*100
=125% increment in k.e

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9.we can use same formulla for next question also...

k.e1/(k.e1-0.19k.e1)=[p1/p2]²

=(1/0.81)= [p1/p2]²

or [p1/p2]=1/0.9

or p2= p1/0.9

or decrease in momentum=10%

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Hope this will help you..

Answer 2

9) Decrease in kinetic energy % = 19%
% decrease in momentum
={ 10- (√100y) }10
= {(10-√100-19)}10
={(10-9)}10
=10%
8)Increase in momentum =50%
% increase in Kinetic energy= (200+x)x/100
=(200+50)50/100
=250×50/100
=25×5
=125%

HOPE IT HELPS!!

SORRY FOR DELAY