plzzz only 15 min left to go to school....plzz help
Attachments:
Answers
Answered by
3
distance between two points with the coordinates(x1,y1) &(x2,y2)
= √[(x2-x1)²+(y2-y1)²]
Given
(x1,y1) = (at1²,2at1)
&(x2,y2) = (at2², 2at2)
•°• distance b/w them
=√[a(t2-t1)²+2a(t2-t1)²]
=√[(a+2a)(t2-t1)²]
= √[(3a)(t2-t1)²]
= [√(3a)] * (t2-t1)
;)
hope it helps
= √[(x2-x1)²+(y2-y1)²]
Given
(x1,y1) = (at1²,2at1)
&(x2,y2) = (at2², 2at2)
•°• distance b/w them
=√[a(t2-t1)²+2a(t2-t1)²]
=√[(a+2a)(t2-t1)²]
= √[(3a)(t2-t1)²]
= [√(3a)] * (t2-t1)
;)
hope it helps
Similar questions