Question

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10 years hence, the age of the father is 2 times the age of his son. 10years ago the age is 6 times the age of his son. find the present ages.​​

Answer 1

Answer:7:3

Step-by-step explanation:

Let the present age of father and son be x and y years respectively.

10 years ago

Father's age was (x-10) years and son's age was (y-10) years

Acc to ques.

(x-10)=3(y-10)

x-10=3y-30

x-3y=-20 (1)eq

After 5 years,

Age of father will be (x+10) years and that of son will be (y+10) years

Again, (x+10)=2(y+10)

x+10=2y+20

x-2y=10 (2)eq

Solving equations 1 and 2

y=30 and x= 70