Question

Plzzz s this question its very urgent plz plz plz

Answer 1

Answer:

Step-by-step explanation:

(x) ² + (x+1)² + (x+2)² + (x+3)² + (x+4)² = 1455

X² + x² + 1 + 2x + x² + 4 + 4x + x² + 9 + 6x + x² + 16 + 8x = 1455

5x² + 20x + 30 = 1455

5x² + 20x +30 - 1455 = 0

5x² + 20x -1425 = 0

5(x² + 4x -285) = 0

X² + 4x -285 = 0

Solve this eq

Answer 2

Answer:

15,16,17,18,19

Step-by-step explanation:

Let five consecutive natural numbers be x, (x + 1),(x + 2),(x + 3),(x + 4).

Given that Sum of squares of five numbers is 1455.

⇒ x² + (x + 1)² + (x + 2)² + (x + 3)² + (x + 4)² = 1455

⇒ x² + x² + 1 + 2x + x² + 4 + 4x + x² + 9 + 6x + x² + 16 + 8x = 1455

⇒ 5x² + 20x + 30 = 1455

⇒ 5x² + 20x - 1425 = 0

⇒ x² + 4x - 285 = 0

⇒ x² - 15x + 19x - 285 = 0

⇒ x(x - 15) + 19(x - 15) = 0

⇒ (x - 15)(x + 19) = 0

⇒ x = 15, -19 {∵ Neglect negative values}

⇒ x = 15

When x = 15:

x + 1 = 16

x + 2 = 17

x + 3 = 18

x + 4 = 19.

Therefore, the five numbers are 15,16,17,18 and 19 respectively.

Hope it helps!