Plzzz solv it fast no 11 in the following image through logarithm
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Answer is in pic.... .......
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log(a+b/2)=1/2(loga+logb)
log(a+b/2)=log√a+log√b
log(a+b/2)=log√a√b
Removing log on both the sides
a+b/2=√a√b
a+b=2√ab
(√a)²+(√b)²-2√ab=0
a²-2ab+b²=(a-b)²
(√a-√b)²=0
Putting square root on both the sides
√a=√b
Removing square root on both the sides
a=b
Hence proved
Hope it helps!!!
log(a+b/2)=log√a+log√b
log(a+b/2)=log√a√b
Removing log on both the sides
a+b/2=√a√b
a+b=2√ab
(√a)²+(√b)²-2√ab=0
a²-2ab+b²=(a-b)²
(√a-√b)²=0
Putting square root on both the sides
√a=√b
Removing square root on both the sides
a=b
Hence proved
Hope it helps!!!
hrik21:
you have done in a very hard method friend
ok no means
Yeah!
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