Plzzz solv it fast vii convert into exponential form and answer is - 8
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3
log (256 base 0.5)
= log( 2^8 base 2^-1)
we know concept
log( a base c^x ) = 1/x log( a base c )
also log( a^x base a ) = x log( a base a )
= x
use both concept here
- log(2^8 base 2)
= -8 ( answer )
= log( 2^8 base 2^-1)
we know concept
log( a base c^x ) = 1/x log( a base c )
also log( a^x base a ) = x log( a base a )
= x
use both concept here
- log(2^8 base 2)
= -8 ( answer )
abhi178:
see the answer
Answered by
2
1)256= 2^8
2)0.5= 5/10=1/2=2^-1
We are using below laws
3)log a^n= n*log a
4)log a^m base a^n = m/n *log a base a
5)log a base a =1
Now
log 256 base 0.5 = log 2^8 base 2^-1
= 8/(-1) log 2 base 2
= -8
2)0.5= 5/10=1/2=2^-1
We are using below laws
3)log a^n= n*log a
4)log a^m base a^n = m/n *log a base a
5)log a base a =1
Now
log 256 base 0.5 = log 2^8 base 2^-1
= 8/(-1) log 2 base 2
= -8
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