Question

plzzz solve it immediately​

Answer 1

(2487)^395

Well, always in these kind of sums, check out for the last digit of the number you have because, the last digit will be decided only on this.
Here 7 is the last number , so let's analyse for 7
7^1 = 7 Last digit is 7
7^2 = 49 Last digit is 9
7^3 = 343 Last digit is 3
7^4 Last digit is 1

And this chain would go on continuing.

So, we can say that for any power that is of the form for 7 as the last digit in the given number

(4m+1) Last digit will be 7
(4m+2) Last digit will be 9
(4m+3) Last digit will be 3
(4m) Last digit will be 1

Now,
Because 395 = 392 + 3
So, 396 is of the form 4m+3

So,
The last digit here will be 3 because the last digit for 4m+3 is 3.

Similarly, analysis can be done for other last digits of given numbers.

Answer 2

Answer:

(2487)^395

Well, always in these kind of sums, check out for the last digit of the number you have because, the last digit will be decided only on this.

Here 7 is the last number , so let's analyse for 7

7^1 = 7 Last digit is 7

7^2 = 49 Last digit is 9

7^3 = 343 Last digit is 3

7^4 Last digit is 1

And this chain would go on continuing.

So, we can say that for any power that is of the form for 7 as the last digit in the given number

(4m+1) Last digit will be 7

(4m+2) Last digit will be 9

(4m+3) Last digit will be 3

(4m) Last digit will be 1

Now,

Because 395 = 392 + 3

So, 396 is of the form 4m+3

So,

The last digit here will be 3 because the last digit for 4m+3 is 3.