Question

plzzz solve this friends....⬆️⬆️⬆️⬆️⬆️⬆️⬆️

Answer 1

First take LCM of the equation you will get

$35x {}^{2} + 12x + 1= 0$

$35 {x}^{2} + 7x + 5x + 1 = 0$

$7x(5x + 1) + 1(5x + 1) = 0$

$(7x + 1)(5x + 1) = 0$

Answer 2

Given Equation is x^2 + (12/35)x + (1/35)

= > (1/35)[35x^2 + 12x + 1]

= > (1/35)[35x^2 + 5x + 7x + 1]

= > (1/35)[5x(7x + 1) + 1(7x + 1)]

= > (1/35)(5x + 1)(7x + 1).

$= > (5x + 1)(\frac{7x + 1}{35})$

$= > (5x + 1)(\frac{7x}{35} + \frac{1}{35})$

$= > (5x + 1)(\frac{x}{5} + \frac{1}{35} )$

Hope this helps!