Question

Using logical operators, 1 AND 0 = _____.

Answer 1

Here, the radius r = 42 cm is given.

The wire is in the form of a circle.

The length of the wire is its circumference, that is, 2*π*r = 2*(22/7)*42 = 264 cm.

Now, since the same wire is bent into a square, the length of the wire remains constant.

Let x be the side of square.

Perimeter of the square = 264 cm

That is, 4*x = 264 cm

or, x = 264/4 = 66 cm

Area of the square = x*x = 66*66 = 4356 cm2

And, area of the circle = π*r2 = (22/7)*42*42 = 5544 cm2

Difference between enclosed areas= 5544-4356 =1188 cm2