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MATHS
A milk container is in the form of frustum of a cone, whose volume is 10459cm3. The radii of lower and upper circular ends at 8 cm and 20 cm respectively. Find the cost of metal sheet used in making the container at the rate of Rs. 2/- per square centimeter.
December 20, 2019Bhavin Tewary
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For frustum,
Volume (V)=10459cm3
Radius of lower circular end (r1)=8cm
Radius of upper circular nd (r2)=20cm
TNow,
Volume of frustum =3πh(r12+r22+r1r2)
10459=722×h(64+400+160)
⇒h=22×62410459×7=5.33cm
Now, slant height (l) is given as-
l=h2+(r1−r2)2
⇒l=28.40+144=13.13cm
Therefore,
Total area of the frustum (A)=π(r1
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