Question

plzzz solve this question​

Answer 1

Answer:

hope you got your answer

Answer 2

Answer:

$\sqrt{3} { x }^{2} - 4x + \sqrt{3 } = 0$

$\sqrt{3}x^{2} - 3x - x + \sqrt{3} = 0$

√3x(x-√3)-1(x-√3)=0

(√3x-1)(x-√3)

(√3x-1)=0. (x-√3)=0

√3x=1. x=√3

x=1/√3. x=√3