Question

Plzzz solve this question plzzzzzzzzzzzzz

Answer 1

$\frac{ {a}^{2} }{9} - \frac{ {b}^{2} }{16} \\ \\ = { (\frac{a}{3}) }^{2} - { (\frac{b}{4} )}^{2} \\ \\ = ( \frac{a}{3} + \frac{b}{4} )( \frac{a}{3} - \frac{b}{4} )$

[ x^2 - y^2 = (x+y) (x-y)]

Answer 2

here's your answer ...