Question

plzzz tell mi answer ch-understanding quardilatrals

Answer 1

actually u study in DAV in class 8th I am also in same class and school so I had the question and figure that is why I tried to answer
(i) ΔABC≈ΔADC
AB=AD(given)
BC=DC(given)
AC=AC(common)
hence ΔABC≈ΔADC by SSS
(ii) AOB≈AOD
AB=AD(given)
AO=OA(common)
BO=OD(diagonal bisect each other equally)
(iii) AC(perpendicular to) BD
AS diagonals cut each other at 90°
(iv)ACbisects BD
as diagonals of a quadrilateral bisect each other at 90°


Thnx and sorry if any answer is not corrct