Question

Plzzz tell this i will mark u as brainlist

Answer 1

Answer:

P(0,4√3), (0, -4√3) and R(4,0)

Step-by-step explanation:

Given that base QR of ΔPQR lies on x-axis.

Let the coordinates of R be (x,0).

⇒ 0 = -4 + x/2

⇒ -4 + x = 0

⇒ x = 4.

Hence, the coordinates of R are (4,0).

Now, P lies on y-axis.

Let its coordinates be P(0,y).

∴ PQ = QR = PR(Equilateral)

Consider, PQ = QR.

On squaring both sides, we get

⇒ PQ² = QR²

⇒ (0 + 4)² + (y - 0)² = (4 + 4)² + 0²

⇒ 4² + y² = 8²

⇒ y² = 48

⇒ y = ±4√3

Therefore, Required coordinates are:

R(4,0), P(0,±4√3).

Hope it helps!

Answer 2

here we have

using section formula

coordinates of R=(4,0)

now using distance formula we have PQ=PR

we getP=(0,y)

again we have PQ=QR

using dist formula we get y coordinate as √48

coordinates of P=(0,√48)