Question

plzzzz ans......Logarithms......Thnk u

Answer 1

log3 m = x
m = 3^x
take cube both sides,
m³ = (3^x)³ = 3^3x
3^3x = m³ -------(1)

again,
log3 n = y
n = 3^y
take square both sides,
n² = (3^y)² = 3^2y
3^2y = n² --------(2)

now,
3^(1 - 2y + 3x) = 3.3^(-2y) .3^3x
= 3.3^3x/3^2y
put equations (1) and (2)
= 3.m³/n²
= 3m³/n²