Math, asked by khushimudiraj1, 1 year ago

Plzzzz ans. My 30th question

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Answered by ARoy
1
 a^{x}= c^{q}=b; c^{y}= a^{z}=d
∴,  a^{x}^{y}=c^{q}^{y}
or,  a^{xy}=a^{zq} [∵,  c^{y}= a^{z}  ]
or, xy=qz (Proved)
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