Plzzzz answer my question as soon as possible.......!!! I will mark as brainliest....!!
If A and B have their birthdays in non-leap year .Find the probability that they celebrate their birthdays on same day every year.
Anonymous:
Answer will be 2/7
Plz elaborate dea..!
see as we know that there are 366 days in a year and seven days in a week
so when we divide 366 by 7 we get 2 as remainder and 51 as quoitent
So now we can see that the two days can be any day the can be the day of there birthday on same day or the other day so the probability would come 2/7
Answers
Answered by
0
I think 1/365
I'm not sure
I'm not sure
mera glat h
Nope
u r also r8dea
but I can only mark 1 q. As brainliest....so sry
r8dea???
I mean ur answer is right...
ok
Answered by
0
Total no of days = 365
Favourable outcome= 1( as they will have their bday on same day)
Probability = 1/365
Favourable outcome= 1( as they will have their bday on same day)
Probability = 1/365
Thank u
Most wlcm
good answer
wright
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