Question

plzzzz.. help........... ​

Answer 1

Answer:

tan A = 3/4

tan = BC/AB

BC = 3x , AB = 4x

AC = 5x ( by Pythagoras thm)

Sin A =O/H =>3x/5x => 3/5

SinC = O/H=> 4x/5x => 4/5

CosA = A/H =>4x/ 5x => 4/5

Cos C = A/H =>3x/5x => 3/5

SinACosC + CosAsinC

3/5 × 3/5 + 4/5 × 4/5

=> 9/25 + 16/25

=> 25/25

=> 1

Answer 2

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Given in △ ABC, ∠B=90°

This given A+C=180−90° =90°-----(1)

Now,

sinA.cosC+cosA.sinC

=sin(A+C)

=sin(90° )=1