Question

Plzzzz help me..... ​

Answer 1

${\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{Distance \:b/w\: planet\:\&\: Earth = 2.5 \times10^{7}}$

$\:\:\:\:\bullet\:\:\:\sf{Gravitational \:force = 3.82 \times 10^{18}}$

$\:\:\:\:\bullet\:\:\:\sf{Mass \:of\: both \: planets = 5.98 \times 10^{24}}$

${\mathfrak{\underline{\red{\:\:\:To \:Find:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{Universal\: Gravitation\: Constant}$

${\mathfrak{\underline{\pink{\:\:\: Formula\:Applied:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{F = \dfrac{Gm_1m_2}{r^2}}$

${\mathfrak{\underline{\orange{\:\:\: Calculation:-\:\:\:}}}}$

☯ Using Newton's Law Of Gravitation:-

$\dashrightarrow\:\: \sf{F = \dfrac{Gm_1m_2}{r^2}}$

$\dashrightarrow\:\: \sf{3.82\times 1{0}^{18}=\dfrac{G\times (5.98\times 1{0}^{24})^2}{(2.5\times 10^9)^2}}$

$\dashrightarrow\:\: \sf{3.82\times 10^{18}=\dfrac{G\times </p><p>35.76\times 10^{48}}{6.25\times 10^{18}}}$

$\dashrightarrow\:\: \sf{ G=\dfrac{3.82\times 10^{18}\times 6.25\times 10^{18}}{35.76\times 10^{48}}}$

$\dashrightarrow\:\:{\boxed{\sf{\red{G=6.67\times 10^{-11} N{m}^{2} k{g}^{-2}}}}}$

Answer 2

Answer:

${\mathfrak{\underline{\pink{\:\:\: Given:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{Distance \:b/w\: planet\:\&\: Earth = 2.5 \times10^{7}}$

$\:\:\:\:\bullet\:\:\:\sf{Gravitational \:force = 3.82 \times 10^{18}}$

$\:\:\:\:\bullet\:\:\:\sf{Mass \:of\: both \: planets = 5.98 \times 10^{24}}$

${\mathfrak{\underline{\orange{\:\:\:To \:Find:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{Universal\: Gravitation\: Constant}$

${\mathfrak{\underline{\blue{\:\:\: Formula\:Applied:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{F = \dfrac{Gm_1m_2}{r^2}}$

${\mathfrak{\underline{\orange{\:\:\: Calculation:-\:\:\:}}}}$

☯ Using Newton's Law Of Gravitation:-

$\dashrightarrow\:\: \sf{F = \dfrac{Gm_1m_2}{r^2}}$

$\dashrightarrow\:\: \sf{3.82\times 1{0}^{18}=\dfrac{G\times (5.98\times 1{0}^{24})^2}{(2.5\times 10^9)^2}}$

$\dashrightarrow\:\: \sf{3.82\times 10^{18}=\dfrac{G\times </p><p>35.76\times 10^{48}}{6.25\times 10^{18}}}$

$\dashrightarrow\:\: \sf{ G=\dfrac{3.82\times 10^{18}\times 6.25\times 10^{18}}{35.76\times 10^{48}}}$

$\dashrightarrow\:\:{\boxed{\sf{\blue{G=6.67\times 10^{-11} N{m}^{2} k{g}^{-2}}}}}$